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Rhombus Area Calculator

Calculate the area of a rhombus from its two diagonals using the formula A = 1/2 d1 d2.

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A = ½d₁d₂

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Diamond Tile

A diamond-shaped tile with diagonals 30 cm and 20 cm.

Key values: d₁ = 30 cm · d₂ = 20 cm · A = 300 cm²

Baseball Diamond

A baseball infield diamond with diagonals of 27.43 m (90 ft × √2).

Key values: d₁ = 27.43 m · d₂ = 27.43 m · A ≈ 376 m²

Documentation

Rhombus Area

A rhombus is a parallelogram with all four sides equal. Two common area formulas:

From diagonals

A=d1×d22A = \frac{d_1 \times d_2}{2}

The diagonals of a rhombus are perpendicular bisectors of each other, forming four right triangles.

From side and angle

A=s2sin(θ)A = s^2 \sin(\theta)

where ss is the side length and θ\theta is any interior angle.


Key Properties

  • All four sides are equal: a=b=c=d=sa = b = c = d = s
  • Opposite angles are equal; consecutive angles are supplementary
  • Diagonals bisect each other at right angles
  • Each diagonal bisects a pair of opposite angles
  • Relationship between diagonals and sides: s2=(d1/2)2+(d2/2)2s^2 = (d_1/2)^2 + (d_2/2)^2

Special Case: The Square

A square is a rhombus with all right angles (θ=90°\theta = 90°). Since sin90°=1\sin 90° = 1, the area simplifies to A=s2A = s^2. The diagonals of a square are equal: d1=d2=s2d_1 = d_2 = s\sqrt{2}.


Frequently Asked Questions

How do I calculate the area of a rhombus?

Use A=d1×d22A = \frac{d_1 \times d_2}{2}, where d1d_1 and d2d_2 are the two diagonals. Alternatively, use A=s2×sin(θ)A = s^2 \times \sin(\theta), where ss is the side length and θ\theta is any interior angle.

What is the difference between a rhombus and a diamond?

They are the same shape. “Diamond” is the informal name for a rhombus — a quadrilateral with all four sides equal. A rhombus has two pairs of equal opposite angles and perpendicular diagonals.

Is a square a special case of a rhombus?

Yes. A square is a rhombus where all angles are 9090^\circ. Since sin(90)=1\sin(90^\circ) = 1, the area formula simplifies to A=s2A = s^2. The diagonals of a square are equal: d1=d2=s2d_1 = d_2 = s\sqrt{2}.

Why are the diagonals of a rhombus perpendicular?

Because a rhombus is a parallelogram with equal sides, the diagonals bisect each other. The equal side lengths force the four resulting triangles to be congruent right triangles, making the diagonals perpendicular.

How do I find the side length from the diagonals?

Use the Pythagorean theorem on the half-diagonals: s=(d12)2+(d22)2s = \sqrt{\left(\frac{d_1}{2}\right)^2 + \left(\frac{d_2}{2}\right)^2}. Since the diagonals bisect each other at right angles, each side is the hypotenuse of a right triangle formed by half of each diagonal.

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