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Triangle Area Calculator

Calculate triangle area using base and height (\u00BD\u00D7b\u00D7h), Heron\'s formula (SSS), two-sides-and-angle (\u00BD\u00D7a\u00D7b\u00D7sin C), or coordinate method. Step-by-step solutions.

Back to Triangle Calculator

Solve Mode

Select the combination of known values

Details: 2 sides + included angle

Known Values

Enter two sides and the angle between them

The angle between sides a and b

°
Triangle Solver Tips

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Try an Example

Pick a scenario to see how the calculator works, then adjust the values

Triangular Land Plot (SSS)

A triangular field with fence posts 80 m, 100 m, and 60 m apart.

Key values: a = 80 m · b = 100 m · c = 60 m

Triangular Sail (SAS)

A sailboat mainsail with two sides of 6 m and 4 m and an included angle of 70°.

Key values: a = 6 m · b = 4 m · C = 70°

Documentation

Four Ways to Calculate Triangle Area

Depending on what measurements you have, one formula will be more convenient than the others. This calculator supports all four major methods:


Method 1: Base and Height

A=12×b×hA = \frac{1}{2} \times b \times h

The simplest formula. The height (altitude) must be measured perpendicular to the chosen base. This works for all triangles, but you need to know (or be able to measure) the perpendicular height.

Common mistake: Using a slanted side instead of the perpendicular height. The height must form a 90° angle with the base.


Method 2: Heron's Formula (Three Sides)

When you know all three sides but not the height, Heron's formula computes the area directly:

A=s(sa)(sb)(sc)A = \sqrt{s(s-a)(s-b)(s-c)}

where s=a+b+c2s = \frac{a+b+c}{2} is the semi-perimeter.

Example: Triangle with sides 7, 8, 9:

s=7+8+92=12s = \frac{7+8+9}{2} = 12
A=12×5×4×3=72026.83A = \sqrt{12 \times 5 \times 4 \times 3} = \sqrt{720} \approx 26.83

Validity check: For three sides to form a valid triangle, they must satisfy the triangle inequality: the sum of any two sides must exceed the third. If sas - a, sbs - b, or scs - c is negative, the triangle is impossible.


Method 3: Two Sides and Included Angle (SAS)

A=12×a×b×sin(C)A = \frac{1}{2} \times a \times b \times \sin(C)

When you know two sides and the angle between them, this formula is the most direct. It comes from the fact that the height relative to side aa is h=bsin(C)h = b \sin(C).

Example: Sides 10 and 14, included angle 35°:

A=12×10×14×sin(35°)70×0.573640.15A = \frac{1}{2} \times 10 \times 14 \times \sin(35°) \approx 70 \times 0.5736 \approx 40.15

Method 4: Coordinate Geometry (Shoelace Formula)

Given vertices at coordinates (x1,y1)(x_1, y_1), (x2,y2)(x_2, y_2), (x3,y3)(x_3, y_3):

A=12x1(y2y3)+x2(y3y1)+x3(y1y2)A = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|

This is a special case of the shoelace formula for polygon area. The absolute value ensures a positive result regardless of vertex ordering.


Which Method to Use

You know...Best method
Base + perpendicular height12bh\frac{1}{2}bh
All three sidesHeron's formula
Two sides + included angleSAS formula
Vertex coordinatesShoelace formula

Frequently Asked Questions

What is the simplest formula for triangle area?

The simplest formula is A=12×b×hA = \frac{1}{2} \times b \times h, where bb is the base and hh is the perpendicular height. The height must form a 90-degree angle with the chosen base. This works for all triangles but requires knowing the perpendicular height.

How does Heron's formula work?

Heron's formula calculates area from three side lengths: A=s(sa)(sb)(sc)A = \sqrt{s(s-a)(s-b)(s-c)}, where s=a+b+c2s = \frac{a+b+c}{2} is the semi-perimeter. For example, a triangle with sides 7, 8, 9 has s=12s = 12 and area 12×5×4×326.83\sqrt{12 \times 5 \times 4 \times 3} \approx 26.83.

When should I use the SAS area formula?

Use the SAS formula A=12×a×b×sin(C)A = \frac{1}{2} \times a \times b \times \sin(C) when you know two sides and the angle between them. It is the most direct method for this case, since the perpendicular height equals bsin(C)b \sin(C).

What is the shoelace formula for triangle area?

The shoelace formula computes area from vertex coordinates: A=12x1(y2y3)+x2(y3y1)+x3(y1y2)A = \frac{1}{2}|x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|. The absolute value ensures a positive result regardless of vertex ordering. It is ideal when you have coordinate geometry data.

How do I check if three sides form a valid triangle?

Three sides form a valid triangle if and only if the sum of any two sides exceeds the third (the triangle inequality). Equivalently, when computing Heron's formula, if any of sas-a, sbs-b, or scs-c is negative or zero, the triangle is impossible.

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