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Simpson's Rule Calculator

Apply Simpson's 1/3 rule to approximate definite integrals with error analysis and step-by-step solution.

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Enter a mathematical expression using x as the variable.

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Basic Polynomial

Integrate x^2 from 0 to 1 using Simpson's rule. Exact answer: 1/3.

Key values: x^2 · [0, 1] · Simpson's rule

Trigonometric Integral

Integrate sin(x) from 0 to pi. Exact answer: 2.

Key values: sin(x) · [0, pi] · Exact: 2

Area Under a Bell Curve

Approximate the Gaussian integral e^(-x^2) from -3 to 3.

Key values: e^(-x^2) · [-3, 3] · Gaussian

Documentation

Simpson's 1/3 Rule

Simpson's rule approximates definite integrals by fitting parabolas (quadratic polynomials) through consecutive groups of three points, rather than using straight lines (trapezoidal) or flat tops (midpoint). This gives O(h4)O(h^4) convergence — dramatically faster than the O(h2)O(h^2) of trapezoidal or midpoint rules.

abf(x)dxh3[f(x0)+4odd if(xi)+2even if(xi)+f(xn)]\int_a^b f(x)\,dx \approx \frac{h}{3}\left[f(x_0) + 4\sum_{\text{odd } i} f(x_i) + 2\sum_{\text{even } i} f(x_i) + f(x_n)\right]

where h=(ba)/nh = (b-a)/n and nn must be even.


Error Bound

ES(ba)5180n4maxx[a,b]f(4)(x)|E_S| \leq \frac{(b-a)^5}{180n^4} \max_{x \in [a,b]} |f^{(4)}(x)|

The error depends on the fourth derivative of ff. This means Simpson's rule is exact for polynomials up to degree 3 (since their fourth derivative is zero).

Practical tip: Doubling nn reduces the error by a factor of 16 (since 24=162^4 = 16). With just 10 subdivisions, Simpson's rule often achieves 8+ digits of accuracy for smooth functions.


Why Simpson's Rule Is the Default

Among the three numerical methods this calculator supports, Simpson's rule offers the best accuracy per function evaluation. For smooth functions, it typically matches the exact answer to machine precision with far fewer subdivisions than the alternatives.

  • vs. Trapezoidal: Same number of function evaluations, but 4th-order convergence vs. 2nd-order. For n=100n = 100, Simpson's error is roughly 10410^4 times smaller.
  • vs. Midpoint: Midpoint avoids endpoint singularities, but for smooth functions Simpson's converges much faster.

When Not to Use Simpson's Rule

  • Endpoint singularities: If f(x)f(x) is undefined at an endpoint (e.g., 1/x1/\sqrt{x} at 0), the midpoint rule is more robust since it avoids evaluating at endpoints.
  • Highly oscillatory functions: Functions with rapid oscillations need very fine subdivisions regardless of method. Adaptive quadrature may be better.
  • Odd number of intervals: Simpson's rule requires an even number of subdivisions. If forced to use an odd number, the trapezoidal rule works.

Frequently Asked Questions

What is Simpson's 1/3 rule?

Simpson's 1/3 rule approximates a definite integral by fitting parabolas through consecutive groups of three points. It achieves O(h4)O(h^4) convergence, meaning doubling the number of subdivisions reduces the error by a factor of 16.

Why does Simpson's rule require an even number of subintervals?

Each parabolic segment spans two consecutive subintervals (three points). If nn is odd, the last subinterval has no partner to complete a parabola, so the method cannot be applied uniformly.

How accurate is Simpson's rule compared to the trapezoidal rule?

For the same number of function evaluations, Simpson's rule is dramatically more accurate for smooth functions. With n=100n = 100 subdivisions, Simpson's error is roughly 10410^4 times smaller than the trapezoidal rule's error.

Is Simpson's rule exact for polynomials?

Yes, Simpson's rule is exact for polynomials of degree 3 or less. The error bound depends on the fourth derivative of the integrand, which is zero for cubics and lower-degree polynomials.

When should I avoid using Simpson's rule?

Avoid Simpson's rule when the function has singularities at the integration endpoints (use the midpoint rule instead), when the function oscillates rapidly (consider adaptive quadrature), or when you are limited to an odd number of subintervals.

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