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Definite Integral Calculator
Calculate the exact value of any definite integral with step-by-step solutions and shaded area visualization.
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Basic Polynomial
Integrate x^2 from 0 to 1 using Simpson's rule. Exact answer: 1/3.
Key values: x^2 · [0, 1] · Simpson's rule
Trigonometric Integral
Integrate sin(x) from 0 to pi. Exact answer: 2.
Key values: sin(x) · [0, pi] · Exact: 2
Area Under a Bell Curve
Approximate the Gaussian integral e^(-x^2) from -3 to 3.
Key values: e^(-x^2) · [-3, 3] · Gaussian
The Definite Integral
The definite integral of from to accumulates the signed area between the curve and the x-axis:
where is any antiderivative of . This is the Fundamental Theorem of Calculus — it connects differentiation and integration.
Key Properties
| Property | Formula |
|---|---|
| Linearity | |
| Reversing limits | |
| Splitting interval | |
| Zero-width | |
| Comparison | If on , then |
Evaluation Example
Compute:
Signed vs. Total Area
The definite integral gives signed area — regions below the x-axis contribute negatively. For the total area(always positive), integrate the absolute value:
In practice, find where , split at those points, and negate the integral on intervals where is negative.
Frequently Asked Questions
What is a definite integral?
A definite integral computes the signed area between the curve and the x-axis over the interval . By the Fundamental Theorem of Calculus, it equals , where is any antiderivative of .
What is the difference between signed area and total area?
Signed area counts regions below the x-axis as negative, so they subtract from the total. Total area uses so all regions contribute positively. For example, for from to , the signed area is 0 but the total area is 4.
What does the Fundamental Theorem of Calculus say?
The Fundamental Theorem connects differentiation and integration. It states that if is an antiderivative of , then the definite integral from to of equals . This transforms the problem of computing area into evaluating a function at two points.
Can a definite integral be negative?
Yes. When is below the x-axis over most of the interval, the integral is negative because the signed area below the axis outweighs the area above it.
What happens when the upper and lower bounds are reversed?
Reversing the bounds negates the integral: . This is one of the fundamental properties of definite integrals.
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