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nth Root of Complex Number Calculator

Find all n distinct nth roots of a complex number, displayed as equally-spaced points on a circle.

Back to Complex Number Calculator

Real component a in z₁ = a + bi

Imaginary component b in z₁ = a + bi

Positive integer n ≥ 2. Returns all n distinct roots.

Try an Example

Pick a scenario to see how the calculator works, then adjust the values

Signal Addition

Add two phasor signals in complex form to find the resultant.

Key values: z₁ = 3 + 4i · z₂ = 1 − 2i · Addition

Circuit Impedance

Divide two impedances to compute the transfer ratio.

Key values: z₁ = 3 + 4i · z₂ = 1 + 2i · Division

De Moivre Power

Raise a complex number to the 10th power using De Moivre's theorem.

Key values: z₁ = 1 + i · n = 10 · Power

Cube Roots of −8

Find all three cube roots of −8, visualized as equidistant points on a circle.

Key values: z₁ = −8 + 0i · n = 3 · nth Root

Documentation

nth Roots of a Complex Number

Every nonzero complex number has exactly nn distinct nnth roots. Given z=r(cosθ+isinθ)z = r(\cos\theta + i\sin\theta):

zk=r1/n[cos ⁣(θ+2πkn)+isin ⁣(θ+2πkn)]z_k = r^{1/n}\left[\cos\!\left(\frac{\theta + 2\pi k}{n}\right) + i\sin\!\left(\frac{\theta + 2\pi k}{n}\right)\right]

for k=0,1,,n1k = 0, 1, \ldots, n-1. Each value of kk gives a different root.


Geometric Arrangement

The nn roots are equally spaced around a circle of radius r1/nr^{1/n}, separated by angles of 2π/n2\pi/n radians (360°/n360°/n). This means:

  • Square roots (n=2n=2): two points diametrically opposite
  • Cube roots (n=3n=3): vertices of an equilateral triangle
  • Fourth roots (n=4n=4): vertices of a square
  • In general: vertices of a regular nn-gon

Roots of unity: The nnth roots of 11 form a cyclic group under multiplication. The primitive root ω=e2πi/n\omega = e^{2\pi i/n} generates all others: 1,ω,ω2,,ωn11, \omega, \omega^2, \ldots, \omega^{n-1}.


Worked Example: Cube Roots of 8

Find all cube roots of 88. In polar form: 8=8(cos0+isin0)8 = 8(\cos 0 + i\sin 0).

zk=2[cos ⁣(2πk3)+isin ⁣(2πk3)]z_k = 2\left[\cos\!\left(\frac{2\pi k}{3}\right) + i\sin\!\left(\frac{2\pi k}{3}\right)\right]
  • k=0k=0: z0=2z_0 = 2 (the obvious real root)
  • k=1k=1: z1=2(cos120°+isin120°)=1+i3z_1 = 2(\cos 120° + i\sin 120°) = -1 + i\sqrt{3}
  • k=2k=2: z2=2(cos240°+isin240°)=1i3z_2 = 2(\cos 240° + i\sin 240°) = -1 - i\sqrt{3}

These three roots form an equilateral triangle of radius 2 centered at the origin.


Frequently Asked Questions

How many nth roots does a complex number have?

Every nonzero complex number has exactly nn distinct nnth roots. For example, the number 8 has three cube roots: 22, 1+i3-1 + i\sqrt{3}, and 1i3-1 - i\sqrt{3}. The fundamental theorem of algebra guarantees that zn=wz^n = w always has nn solutions in the complex plane.

Why are the nth roots equally spaced on a circle?

Each root has the same modulus r1/nr^{1/n} but a different argument. Consecutive roots differ by an angle of 2πn\frac{2\pi}{n} radians (360n\frac{360^\circ}{n}). This equal spacing means the nn roots form the vertices of a regular nn-gon centered at the origin.

What are roots of unity?

The nnth roots of unity are the nn solutions to zn=1z^n = 1. They lie on the unit circle (radius 1) at angles 2πkn\frac{2\pi k}{n} for k=0,1,,n1k = 0, 1, \ldots, n - 1. The primitive root ω=e2πi/n\omega = e^{2\pi i/n} generates all others as powers: 1,ω,ω2,,ωn11, \omega, \omega^2, \ldots, \omega^{n-1}.

How do you find the cube roots of a negative real number?

Write the number in polar form first. For 8-8: r=8r = 8 and θ=π\theta = \pi. The three cube roots have modulus 81/3=28^{1/3} = 2 and arguments π+2πk3\frac{\pi + 2\pi k}{3} for k=0,1,2k = 0, 1, 2. This yields 2(cos60+isin60)=1+i32(\cos 60^\circ + i\sin 60^\circ) = 1 + i\sqrt{3}, the real root 2-2, and 1i31 - i\sqrt{3}.

Where are complex roots used in practice?

Complex nnth roots appear in signal processing (the discrete Fourier transform uses roots of unity), electrical engineering (AC circuit analysis), control theory (pole placement), and polynomial factoring (splitting xncx^n - c into linear factors).

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